Trial exam every week Russian. Preparation for the OGE in mathematics and for the USE in other subjects
Exercise 1
In the store, all furniture is sold unassembled. The buyer can order the assembly of furniture at home, the cost of which is \(20\%\) of the cost of the purchased furniture. The wardrobe costs 4100 rubles. How much will it cost to buy this cabinet along with the assembly?
Let's find the assembly cost: \(4100\cdot 20:100=820\) rubles. Consequently, the buyer will pay \(4100+820=4920\) rubles for the cabinet and assembly.
Answer: 4920
Task 2
The diagram shows the average monthly air temperature in Minsk for each month in 2003. Months are indicated horizontally, temperatures in degrees Celsius are indicated vertically. Determine from the diagram in which month the average monthly temperature exceeded \(14^\circ C\) for the first time. Write down the number of the month in your answer. (For example, answer 1 means January.)
Task 3
A triangle is depicted on checkered paper with a cell size \(1\times1\). Find the radius of the circumscribed circle.
According to the sine theorem, the ratio of the side length to the sine of the opposite angle is equal to two radii of the circumscribed circle: \[\dfrac a(\sin\alpha)=2R\] a=BC\) . Note that \(\alpha=45^\circ\) , because \(\triangle B"AC"\) is rectangular and isosceles. Consequently, \(\sin\alpha=\dfrac(\sqrt2)2\).
Let us find from the rectangular \(\triangle BHC\) using the Pythagorean theorem \(BC\) : \ Therefore, \
Answer: 5
Task 4
There are three salesmen in the store. Each of them is busy serving a customer with a probability of 0.7, regardless of other sellers. Find the probability that at a random time all three sellers are busy.
The event “all three sellers are busy at the same time” is equal to the event “the first seller is busy AND the second seller is busy AND the third seller is busy”. Since each seller is busy with a probability of 0.7 independently of the others, the probability of this event is equal to the product of the probabilities of the events “first seller is busy”, “second seller is busy” and “third seller is busy”: \
Answer: 0.343
Task 5
Find the root of the equation \[\log_(\frac14)(9-5x)=-3\]
ODZ of this equation: \(9-5x>0\) . Let's decide on ODZ: \[\log_(\frac14)(9-5x)=-3 \quad\Rightarrow\quad 9-5x=\left(\dfrac14\right)^(-3) \quad\Leftrightarrow\quad 9-5x=64 \quad\Leftrightarrow\quad x=-11.\] This answer is suitable for ODZ.
Answer: -11
Task 6
IN isosceles triangle\(ABC\) with base \(AB\) side is \(16\sqrt7\) , \(\sin\angle BAC=0.75\) . Find the height length \(AH\) .
Consider the figure:
Let's do \(CK\perp AB\) . Since the triangle \(ABC\) is isosceles, then \(\angle BAC=\angle ABC\) , therefore, \(\sin \angle ABC=0,75=\frac34\).
Then from \(\triangle CKB\) : \[\dfrac34=\dfrac(CK)(CB) \quad\Rightarrow\quad CK=12\sqrt7.\] Then by the Pythagorean theorem from \(\triangle CKB\) : \
Therefore, since \(CK\) is also a median, i.e. \(AK=KB\) , we have: \(AB=2KB=56\) .
Then from \(\triangle AHB\) : \[\dfrac34=\dfrac(AH)(AB) \quad\Rightarrow\quad AH=42.\]
Answer: 42
Task 7
The figure shows the graph of the function \(y=f"(x)\) - the derivative of the function \(f(x)\) . Find the abscissa of the point at which the tangent to the graph of the function \(y=f(x)\) is parallel to the line \(y=10-7x\) or matches it.
It is necessary to find \(x_0\) , in which a tangent is drawn to \(f(x)\), and this tangent is parallel or coincides with \(y=10-7x\) .
Let the tangent equation be: \(y=kx+b\) . Since it is parallel or the same as \(y=10-7x\) , their slopes are equal, i.e. \(k=-7\) .
The slope of the tangent to \(f(x)\) is equal to the value \(f"(x)\) at the point of tangency \(x_0\) , i.e. \(k=-7=f"(x_0)\) .
Since the derivative is just given on the graph, it is necessary to find such a point with the abscissa \(x_0\) , whose ordinate value \(y_0=f"(x_0)\) is equal to \(-7\) . The figure shows that there is only one point on the chart with ordinate -7 - this is the point \((-2;-7).\)
Answer: -2
Task 8
Given two cylinders. The volume of the first cylinder is \(8\) . The height of the second cylinder is 4 times less, and the radius of the base is 3 times greater than that of the first. Find the volume of the second cylinder.
The volume of a cylinder with height \(h\) and base radius \(R\) is calculated by the formula \ Therefore, for the first cylinder we have the equality: \ The height of the second cylinder is \(\frac14h\) , and the radius of the base is \(3R\ ) . Therefore, its volume is: \
Answer: 18
Task 9
Find the value of an expression \[\dfrac(\sqrt(5,6)\cdot \sqrt(1,4))(\sqrt(0,16))\]
Let's bring everything under one root: \[\sqrt(\dfrac(5,6\cdot 1,4)(0,16))= \sqrt(\dfrac(56\cdot 14)(16))=\sqrt(\dfrac(14\cdot 14) )(4))=\dfrac(14)2=7.\]
Answer: 7
Task 10
A car whose mass is equal to \(m=2000\) kg starts moving with an acceleration that remains unchanged for \(t\) seconds, and covers a distance \(S=1000\) meters during this time. The value of the force (in newtons) applied at that time to the car (engine thrust) is equal to \(F=\dfrac(2mS)(t^2)\) .
Determine the time after the start of the movement of the car, for which it will pass the specified path, if it is known that the force \(F\) applied to the car is \(1600 H\) . Express your answer in seconds.
Substitute the values in the formula: \ since \(t>0\) is time.
Answer: 50
Task 11
Passenger and freight trains travel in the same direction along two parallel railway tracks at speeds of 90 km/h and 30 km/h, respectively. The length of a freight train is 900 meters. Find the length of the passenger train if the time it takes for it to pass the freight train is 1 minute 3 seconds. Give your answer in meters.
The phrase “passenger train passed the freight train” means that at the beginning of the observation, the nose of the passenger train was opposite the tail of the freight train, and at the end, the tail of the passenger train was opposite the nose of the freight train:
We fix two points: the nose of the passenger and the tail of the cargo. Then, at the beginning of the observation, the distance between them was equal to 0 m, and at the end of the observation, the distance between them was equal to the length of the freight train plus the length of the passenger train.
Note that the nose of the passenger train moves away from the tail of the freight train by \(90-30=60\) km per hour. Therefore, the removal rate is \
Let \(l\) m be the length of the passenger train. 1 minute 3 seconds is equal to 63 seconds, so: \
Answer: 150
Task 12
Find the minimum point of the function \(y=x^3-4x^2-3x-13.\)
Find the derivative: \ Find the zeros of the derivative: \ Find the signs of the derivative on the intervals:
The minimum point is the point where the derivative changes its sign from minus to plus, hence \(x_(min)=3\) .
Answer: 3
Task 13
a) Solve the equation \[\dfrac1(\sin^2x)-\dfrac3(\cos \left(\dfrac(11\pi)2+x\right))=-2\]
b) Indicate the roots of this equation that belong to the segment \(\left[-2\pi;-\dfrac(\pi)2\right].\)
a) According to the reduction formula \(\cos \left(\dfrac(11\pi)2+x\right)=\sin x\), therefore, the equation will take the form: \[\dfrac1(\sin^2x)-\dfrac3(\sin x)+2=0\]
Let's make the replacement \(t=\dfrac1(\sin x)\) , then \ Therefore, \(\sin x=1\) , which is equivalent to \(x=\dfrac(\pi)2+2\pi m, m\in\mathbb(Z)\);
\(\sin x=\dfrac12\) , which is equivalent to \(x=\dfrac(\pi)6+2\pi k\) and \(x=\dfrac(5\pi)6+2\pi n\ ) , \(k,n\in\mathbb(Z)\) .
b) Let's take the roots.
\(-2\pi \leqslant \dfrac(\pi)6+2\pi k\leqslant -\dfrac(\pi)2 \quad\Rightarrow\quad -\dfrac(13)(12)\leqslant k\leqslant -\dfrac13\). Since \(k\) is an integer, then \(k=-1\) , hence \(x=-\dfrac(11\pi)6\) .
\(-2\pi \leqslant \dfrac(5\pi)6+2\pi n\leqslant -\dfrac(\pi)2 \quad\Rightarrow\quad -\dfrac(17)(12)\leqslant n\ leqslant -\dfrac23\). Since \(n\) is an integer, then \(n=-1\) , hence \(x=-\dfrac(7\pi)6\) .
\(-2\pi \leqslant \dfrac(\pi)2+2\pi m\leqslant -\dfrac(\pi)2\quad\Rightarrow\quad -\dfrac54\leqslant m\leqslant -\dfrac12\). Since \(m\) is an integer, then \(m=-1\) , hence \(x=-\dfrac(3\pi)2.\)
Answer:
but) \(\dfrac(\pi)6+2\pi k; \dfrac(5\pi)6+2\pi n; \dfrac(\pi)2+2\pi m; \ k,n,m\in \mathbb(Z)\)
b) \(-\dfrac(11\pi)6; -\dfrac(3\pi)2; -\dfrac(7\pi)6\)
Task 14
At the base of the pyramid \(SABCD\) lies a rectangle \(ABCD\) with side \(AB=5\) and diagonal \(BD=9\) . All side edges of the pyramid are \(5\) . A point \(E\) is marked on the diagonal \(BD\) of the base \(ABCD\), and a point \(F\) is marked on the edge \(AS\) so that \(SF=BE=4\) .
a) Prove that the plane \(CEF\) is parallel to the edge \(SB\) .
b) The plane \(CEF\) intersects the edge \(SD\) at the point \(Q\) . Find the distance from the point \(Q\) to the plane \(ABC\) .
a) Extend \(CE\) to the intersection with \(AB\) at the point \(K\) . We get the segment \(FK\) along which the plane \(CEF\) intersects the face \(SAB\) . Consider the base of the pyramid:
\(DE=9-4=5=DC\) , so \(\triangle DEC\) is isosceles. Then \(\angle DCE=\angle DEC=\angle BEK=\angle BKE\), therefore \(\triangle BEK\) is also isosceles and \(BE=BK=4\) . Then \(AK=5-4=1\) .
Note that the side faces \(ASB\) and \(CSD\) are equilateral triangles with side \(5\) . So in \(\triangle AFK\) \(AF=AK=1\) and \(\angle FAK=60^\circ\) , hence it is also equilateral, i.e. \(FK\parallel SB\) ( \(\angle AKF=\angle ABS=60^\circ\) as corresponding to the secant \(AB\) ). Thus, in the plane \(CEF\) there is a line \(FK\) parallel to \(SB\) . Therefore, by feature, the plane \(CEF\) is parallel to \(SB\) .
b) Since the plane \(CEF\parallel SB\) , then it will intersect the plane \(BSD\) along the line \(EQ\) parallel to \(SB\) (otherwise \(EQ\) will intersect \( SB\) , therefore, the plane \(CEF\) will intersect \(SB\) ). Consider \(\triangle BSD\) : 
Note that since all side edges of the pyramid are equal, the height \(SO\) will fall to the intersection point of the diagonals of the base (all triangles \(SAO\) , \(SBO\) , \(SCO\) and \(SDO\) will be equal as rectangular along the leg and hypotenuse, therefore, \(AO=BO=CO=DO\) , therefore, \(O\) is the point of intersection of the diagonals).
Let's draw \(QH\parallel SO\) . Since \(SO\) is perpendicular to the plane \(ABC\) , so is \(QH\perp (ABC)\) . Thus, it is necessary to find \(QH\) .
Since \(EQ\parallel SB\) , then by the Thales theorem: \[\dfrac54=\dfrac(DE)(EB)=\dfrac(DQ)(QS) \quad\Rightarrow\quad \dfrac(DQ)(DS)=\dfrac59\] Because \(\triangle DQH\sim \triangle DSO\)(two corners), then \[\dfrac(DQ)(DS)=\dfrac(QH)(SO) \quad\Rightarrow\quad QH=\dfrac59SO\] Thus, it is necessary to find \(SO\) .
From rectangular \(\triangle SOB\) : \
Consequently, \
Answer:
b) \(\dfrac(5\sqrt(19))(18)\)
Task 15
Solve the inequality \[\dfrac(\log_3(9x)\cdot \log_4(64x))(5x^2-|x|)\leqslant 0\]
Let's find the ODZ of logarithms: \[\begin(cases) 9x>0\\ 64x>0 \end(cases) \quad\Leftrightarrow\quad x>0\] Note that this ODZ has \(|x|=x\) . Then, on the ODZ, according to the rationalization method, the inequality is equivalent to: \[\dfrac((3-1)(9x-1)(4-1)(64x-1))(x(5x-1))\leqslant 0 \quad\Leftrightarrow\quad \dfrac((9x-1 )(64x-1))(x(5x-1))\leqslant 0\] We solve this inequality by the interval method:
Therefore, the solution will be \(x\in \left(0;\dfrac1(64)\right]\cup\left[\dfrac19;\dfrac15\right)\).
Intersecting this answer with ODZ \(x>0\) , we get the final answer: \\cup\left[\dfrac19;\dfrac15\right)\]
Answer:
\(\left(0;\dfrac1(64)\right]\cup\left[\dfrac19;\dfrac15\right)\)
Task 16
The line passing through the midpoint \(M\) of the hypotenuse \(AB\) right triangle\(ABC\) , is perpendicular to \(CM\) and intersects \(AC\) at the point \(K\) . In this case, \(AK:KC=1:2\) .
a) Prove that \(\angle BAC=30^\circ\) .
b) Let the lines \(MK\) and \(BC\) intersect at the point \(P\) , and the lines \(AP\) and \(BK\) intersect at the point \(Q\) . Find \(KQ\) if \(BC=2\sqrt3\) .
a) Let \(AK=x, \KC=2x\) . Let's draw \(BL\parallel MK\) . Then by the Thales theorem \[\dfrac(BM)(MA)=\dfrac11=\dfrac(LK)(KA) \quad\Rightarrow\quad LK=KA=x \quad\Rightarrow \quad CL=x.\]
Then also by the Thales theorem: \[\dfrac(CL)(LK)=\dfrac11=\dfrac(CO)(OM) \quad\Rightarrow\quad CO=OM.\] Therefore, \(BO\) is the median and height ( \(MK\perp CM, \BO\parallel MK \quad\Rightarrow\quad BO\perp CM\)), so \(\triangle CBM\) is isosceles and \(CB=BM\) . Hence \(CB=\frac12BA\) . Since the leg, which is half the hypotenuse, lies opposite the angle at \(30^\circ\) , then \(\angle BAC=30^\circ\) .
b) Consider \(\triangle PMC\) : \(\angle PMC=90^\circ\) . Since \(BM=BC\) , then \(BM=BC=BP\) , that is, \(B\) is the middle of \(CP\) ( \(\angle BCM=\angle BMC=60^\circ\), Consequently, \(\angle CPM=30^\circ=\angle PMB\), hence \(BP=BM\) ).
Let's draw \(BS\parallel AP\) . Then \(BS\) is the midline of the triangle \(APC\) . So \(CS=SA\) .
From rectangular \(\triangle ABC\) : \[\mathrm(tg)\,30^\circ=\dfrac(BC)(AC) \quad\Rightarrow\quad AC= BC\cdot \sqrt3=6.\] Therefore, \(CS=SA=3\) , and since \(CK:KA=2:1\) , then \(KA=2\) and \(SK=1\) .
notice, that \(\triangle BKS\sim \triangle QKA\) on two angles (\(\angle BKS=\angle QKA\) as vertical, \(\angle BSK=\angle QAK\) as lying across at \(AQ\parallel BS\) and \(SA\) secant). Consequently, \[\dfrac(SK)(AK)=\dfrac12=\dfrac(BK)(KQ) \quad\Rightarrow\quad KQ=2BK.\] Let's find \(BK\) .
By the Pythagorean theorem from \(\triangle BKC\) : \
Consequently, \
Answer:
b) \(4\sqrt7\)
Task 17
:has a unique solution.
Let's make the replacement \(t=5^x, t>0\) and move all terms into one part: \
Received quadratic equation, whose roots, according to Vieta's theorem, are \(t_1=a+6\) and \(t_2=5+3|a|\) . In order for the original equation to have one root, it is enough that the resulting equation with \(t\) also has one (positive!) root.
We note at once that \(t_2\) for all \(a\) will be positive. Thus, we get two cases:
1) \(t_1=t_2\) : \ &a=-\dfrac14 \end(aligned) \end(gathered) \right.\]
A) Assume that the equality \[\dfrac(a+c)(b+d)=\dfrac7(23)\] Then \(a+c=7k\) , \(b+d=23k\) , where \(k\) is natural number. Since \(a, c\) - double figures, then smallest value\(a+c\geqslant 10+11=21\) , so \(7k\geqslant 21 \quad\Rightarrow\quad k\geqslant 3\).
Take \(k=3\) . Then \(a+c=21\) , \(b+d=69\) . Therefore, we can take, for example, \(a=10\) , \(c=11\) , \(b=16\) , \(d=53\) .
Answer: yes.
b) Let's assume that \
Let's rewrite this equation in a different form: \
Let's prove that \
It will follow from this that the assumption is false and such an equality is impossible. Consider the first inequality. \
Since all numbers are two-digit, \(11b \geqslant 11\cdot 10=110\). Therefore, \(d<11b\)
, а значит и левая дробь всегда строго больше правой.
The second inequality is proved similarly.
Therefore, the answer is: no.
c) Since all numbers are natural, from \(a>4b\) we can conclude that \(a\geqslant 4b+1\) . Similar to \(c\geqslant 7d+1\) . Substitute: \[\dfrac(a+c)(b+d) \geqslant \dfrac(4b+1+7d+1)(b+d)=4+\dfrac(3d+2)(b+d)\] Thus, the expression will take the smallest value at the smallest value of the expression \(\dfrac(3d+2)(b+d)\) . Since the fraction is smaller, the larger its denominator (for a fixed numerator), then we maximize the denominator (that is, we maximize \(b\) ).
Since \(a\) is two-digit, the maximum value for \(a\) is 99, hence \(4b+1\leqslant 99\) , hence \(b\leqslant 24\) . Thus, we get: \[\dfrac(a+c)(b+d) \geqslant 4+\dfrac(3d+2)(24+d)=4+\dfrac(3(d+24)+2-72)(d+ 24) =4+3-\dfrac(70)(d+24)\]
Now, in order to make the expression on the right as small as possible, you need to make \(\dfrac(70)(d+24)\) as large as possible, that is, make \(d\) as small as possible.
The smallest value for \(d\) is \(10\) . Consequently: \[\dfrac(a+c)(b+d) \geqslant4+3-\dfrac(70)(10+24)=4\frac(16)(17)\] Thus, if the smallest value \(4\frac(16)(17)\) is reached, then \(b=24\) , \(d=10\) , \(a= 4\cdot 24+1=97 \) , \(c= 7\cdot 10+1=71\) .
Answer:
c) \(4\frac(16)(17)\)
Instruction
for the performance of work
The examination paper consists of two parts containing 25 tasks. Part 1 contains 24 tasks, part 2 contains one task.
For execution examination work 3.5 hours (210 minutes) are allotted for the Russian language.
The answers to tasks 1-24 are a number (number) or a word (several words), a sequence of numbers (numbers). Write your answer in the answer field in the text of the work, and then transfer it according to the instructions below. samples on answer sheet 1.
Task 25 of part 2 is an essay based on the read text. This task is performed on the answer sheet No. 2.
All USE forms are filled in with bright black ink. You can use a gel, capillary or fountain pen.
When completing assignments, you can use a draft. Draft entries do not count towards the assessment of the work.
The points you get for completed tasks are summed up. Try to complete as many tasks as possible and score the most points.
We wish you success!
OPTION 1
Part 1
Read the text and complete tasks 1-3.
| (1) It was believed that the famous Greek mathematician Pythagoras invented musical notation. (2) ... the musical notation known to us originated in the territory of modern Syria a thousand years before Pythagoras developed a system of musical notation, which includes seven musical signs. (3) These conclusions are based on the results of a study of records found in ancient city Ugarit in northwestern Syria in the 50s of the last century. (4) Archaeologists then managed to find recorded musical symbols dating back to the middle of the second millennium BC. (5) In the course of the completed study, experts confirmed that the Ugarit find is the first recording of a musical work in the history of mankind. (6) The lack of other information about the history of music and singing in Syria, scientists explain the influence of disasters, earthquakes and wars, which for a long time made it impossible to obtain the necessary evidence. |
1. Indicate two sentences that correctly convey HOME information contained in the text. Write down the numbers of these sentences.
1) Catastrophes, earthquakes and wars for a long time made it impossible to obtain the necessary evidence of the existence of musical literacy in the middle of the second millennium BC.
2) In the 50s of the last century, in the ancient city of Ugarit in northwestern Syria, archaeologists managed to find the first recorded musical symbols in history, and this disproved the information that Pythagoras invented musical notation.
3) The Ugarit find is the first recording of a musical work in the history of mankind.
4) Before the discovery in the 50s of the last century in Syria of records of musical symbols dating back to the middle of the second millennium BC, it was believed that Pythagoras invented musical notation.
5) Not so long ago, Syrian scientists made the statement that the musical notation known to us originated in the territory of modern Syria a thousand years before Pythagoras developed a system of musical notation, which includes seven musical signs.
Answer:___________________
2 . Which of the following words (combinations of words) should be in place of the gap in the second (2) text sentence? Write down this word (combination of words).
Even Only After All However
Answer _______________________________
3 . Read the fragment of the dictionary entry, which gives the meaning of the word LETTER. Determine the meaning in which this word is used in the second (2) sentence of the text. Write down the number corresponding to this value in the given fragment of the dictionary entry.
LETTER, -a, cf.
1) Written text sent to communicate something to someone. Write a letter to relatives.
2) Ability to write. Learn to read and write.
3) A system of graphic signs for the transmission of information. Verbal-syllabic writing.
4) The manner of the artistic image. Ancient letter icon.
Answer _________________________________________________________
4. One of the following words has an accent error: WRONG the letter denoting the stressed vowel is highlighted. Write out this word.
Garbage chute understood A will strengthen briefly bent
Answer __________________________________
5. One of the suggestions below WRONG highlighted word is used. Correct the lexical error by choosing a paronym for the highlighted word. Write down the chosen word.
The novel shows the life of both the capital and LOCAL nobility. It is difficult for a person with a POOR fantasy to write creative work.
IN FORMER years classmates often gathered in the old park. The advantage of the location of the camp was that the lake extended to the right, and a dirt road ran to the left.
Grandchildren can PAY back for the hospitality of their grandfather with help in the apiary.
______
6. In one of the words highlighted below, a mistake was made in the formation of the word form. Correct the mistake and spell the word correctly.
ripe APRICOTS WILL ignite a fire over THREE Hundred thousand
contrary to PREDICTION A MORE HONEST solution
7 . Establish a correspondence between grammatical errors and sentences in which they are made: for each position of the first column, select the corresponding position from the second column.
| Grammatical errors | Offers |
| A) a violation in the construction of a sentence with participial turnover B) build error complex sentence B) a violation in the construction of a proposal with an inconsistent application D) violation of the connection between the subject and the predicate E) violation of the species-temporal correlation of verb forms | 1) Our memory tends to reduce all color shades to a few colors, which for some reason we have made basic for ourselves. 2) Forgotten memories can be returned by activating the cells responsible for accessing stored information in the brain. 3) M. Gorky included two legends in the story "Old Woman Izergil". 4) In office centers you rarely meet a person without disturbing disorders. 5) In May 1820, Pushkin and the family of General Raevsky went to the Caucasian Mineral water and spent the night in Taganrog in the house of the mayor Papkov. 6) These animals are called stingers because they have special stinging capsules with which they hunt crustaceans and roundworms. 7) Women, in comparison with men, are very little genetically variable, and this is precisely the reason for their high adaptability. 8) In addition to lack of sleep, chronic stress and depression, other disorders can also lead to memory loss. 9) Every year at the end of summer, a meteor shower hits the Earth, despite the fact that in fact we do not see stars at all. |
Write in the table the selected numbers under the corresponding letters.
8 .Determine the word in which the unstressed checked vowel of the root is missing. Write out this word by inserting the missing letter.
t ... printing
sp ... gray
sign...
to ... mpromise
float ... wok
Answer__________________________
9 .Determine the row in which the same letter is missing in both words. Write these words out with the missing letter.
pr ... forced, pr ... fence
without ... artificial, carry
pre...feel, oh...guess
neither ... toss, nor ... to fall
from ... revealed, into ... youths
Answer_________________________
10. Write down the word in which the letter is written in the place of the gap ABOUT. recruit...
look ... wat
commands...
unwind ... roll
penetrate...
Answer _____________________________
11 . Write down the word in which the letter is written in the place of the gap E.
pumped out ... (oil)
imagining ... tsya (figure)
creeping ... tsya (fog)
cleared .... who (path)
infused (tea)
Answer_________________________________
12. Identify the sentence in which NOT with the word is spelled CONTINUOUSLY. Open the brackets and write out this word.
In Russia in the 30s, people (NOT) ate up.
His eyes were cloudy, (NOT) EXPRESSING joy from the meeting.
This locality(NOT) INCLUDED in the list of the most visited by tourists.
Deryugin chose a profession by no means (NOT) EASY.
There are a lot of typos (NOT) NOTICED by the author of the manuscript.
Answer____________________________________
13. Determine the sentence in which both underlined words are spelled ONE. Open the brackets and write out these two words.
(FROM) EVERYWHERE appeared a rider who was in a hurry (AND) so drove the horse that she was exhausted.
SO (SAME), like us, this group of tourists visited (B) NEAR the Proval in Pyatigorsk.
TO (WOULD) please the groom's parents, the girl was friendly, (WHEN) she behaved naturally.
Avdonin THEN (SAME) leaned on mathematics, BECAUSE (THAT) he was going to participate in the subject Olympiad.
(B) CONCLUSION of the ballet music sounded (IN) THE LIKENESS of an adagio.
14. Indicate all the numbers in the place of which it is written NN.
In the courtyard of the house there were (1) s sawn (2) logs by the yard, weaved (3) chairs, a kitchen (4) table, more beautiful (5) with silver (6) paint, harvested (7) with old ones hosts.
15. Set up punctuation marks. Specify two sentences in which you need to put ONE comma. write down numbers these proposals.
1) The hunter and breadwinner at that time was fourteen years old and he did not have enough strength to drag such a vehicle on himself for a long time.
2) The rails could not withstand the tests for deflection and fracture, and, according to Antipov's assumptions, they should have burst in the cold.
3) The steamboat, although it really had already rolled away from the pier, was still not moving along a direct course, but was only turning around.
4) Every minute bells rattled and numbers flew out in a long glass box on the wall.
5) In mid-August, the Smokovnikovs, together with Dasha, moved to St. Petersburg to their large apartment on Panteleimonovskaya.
Answer__________________________________________
16.
Old women (1) carrying in front of them (2) in both hands tin bowls with porridge (3) carefully left the kitchen and sat down to dine at the common table (4) trying not to look (5) at the slogans hung in the dining room (6) (7) composed personally by Alexander Yakovlevich (8) and artistically performed by Alexandra Yakovlevna.
Answer______________________________________
17. Set up punctuation marks. Indicate all the numbers that should be replaced by commas in sentences.
Living sympathy hello (1)
From unattainable heights (2)
Oh (3) do not embarrass (4) I pray (5) the poet!
Don't tempt his dreams!
Lost all my life (6) in a crowd of people,
At times (7) accessible to their passions,
Poet (8) I know (9) superstitious,
But he rarely serves the authorities.
(F. Tyutchev)
Answer________________________________________
18 .Spread punctuation marks. Indicate all the numbers that should be replaced by commas in the sentence.
He told his son (1) what a camera obscura is (2) that a dark box with a small hole (3) and a plate (4) covered with a photosensitive substance (5) is enough (6) to take a picture (7) to stop a moment of life.
Answer________________________________________
19. Set up punctuation marks. Indicate all the numbers that should be replaced by commas in the sentence.
During the night, a lot of new snow piled up (1) the trees were dressed in white (2) and the air was unusually bright (3) transparent and gentle (4) so (5) that (6) when Anna Akimovna looked out the window (7) then she, First of all, I wanted to take a deep breath.
Answer____________________________________________
(1) Our ideas about the ideal of beauty are embodied in external human beauty. (2) External beauty is not only the anthropological perfection of all elements of the body, not only health. (3) This is inner spirituality - a rich world of thoughts and feelings, moral dignity, respect for people and for oneself ... (4) The higher the moral development and the general level of a person’s spiritual culture, the brighter the inner spiritual world is reflected in external features. (5) This glow of the soul, according to Hegel, is increasingly manifested, understood and felt modern man. (6) Inner beauty is reflected in the outer appearance.
(7) The unity of inner and outer beauty is an aesthetic expression of the moral dignity of a person. (8) There is nothing shameful in the fact that a person strives to be beautiful, wants to look beautiful. (9) But, it seems to me, one must have a moral right to this desire. (10) The morality of this aspiration is determined by the extent to which this beauty expresses the creative, active essence of a person.
(11) The beauty of a person manifests itself most clearly when he is engaged in his favorite activity, which, by its nature, emphasizes something good in him, characteristic of his personality. (12) At the same time, his external appearance is illuminated by inner inspiration. (13) It is no coincidence that Miron embodied the beauty of the discus thrower at a moment when the tension of internal spiritual forces is combined with the tension of physical forces, in this combination - the apotheosis of beauty ...
(14) External beauty has its own internal, moral origins. (15) Favorite creativity makes a person beautiful, transforms facial features - makes them subtle, expressive.
(16) Beauty is also created by anxiety, care - what is usually called "the pangs of creativity." (17) Just as grief leaves indelible wrinkles on the face, so creative cares are the most subtle, most skillful sculptor that makes the face beautiful. (18) Conversely, the inner emptiness gives the outer facial features an expression of dull indifference.
(19) If internal spiritual wealth creates human beauty, then inactivity, and even more so immoral activity, destroys this beauty.
(20) Immoral activity disfigures. (21) The habit of lying, hypocrisy, idle talk creates a wandering look: a person avoids looking into the eyes of other people; in his eyes it is difficult to see the thought, he hides it. (22) Envy, selfishness, suspicion, fear that "I will not be appreciated" - all these feelings gradually coarsen the facial features, give it a sullenness, unsociableness. (23) Being yourself, cherishing your dignity - this is the living blood of genuine human beauty.
24) The ideal of human beauty is at the same time the ideal of morality.
(25) The unity of physical, moral, aesthetic perfection - this is the harmony about which so much is said. (V. A. Sukhomlinsky*)
* Vasily Aleksandrovich Sukhomlinsky (1918-1970) - Corresponding Member of the Academy of Pedagogical Sciences of the USSR, Candidate of Pedagogical Sciences, Honored School Teacher of the Ukrainian SSR, Hero of Socialist Labor.
20. Which of the statements correspond to the content of the text? Specify the answer numbers.
1) A person who is improving spiritually does not attach importance to appearance.
2) A person who has experienced anxiety becomes kinder, which means more beautiful.
3) External beauty is a manifestation of the inner spiritual strength of a person.
4) A person is beautiful in moments of creative upsurge.
5) A person who is afraid of being underestimated and envious of others has a sullen expression on his face.
Answer_______________________________________
21. Which of the following statements are true? Specify the answer numbers.
1) Sentences 3, 4 complement and clarify the idea expressed in sentence 2.
2) In sentences 16-18, reasoning is presented.
3) Sentences 20, 21 include a description.
4) Sentences 20-22 contain a narrative.
5) Proposition 25 contains a general conclusion from the author's reasoning.
Answer________________________________________
22. From sentences 7-10 write out antonyms (antonymic pair).
Answer_________________________________________
23. Among sentences 14-18, find one (s) that (s) is connected with the previous one using a single-root word. Write the number(s) of this offer(s).
Answer_______________________________________
24 . Read a fragment of a review based on the text that you analyzed while doing tasks 20-23.
This fragment examines the language features of the text.
Some terms used in the review are missing. Fill in the gaps (A, B, C, D) with the numbers corresponding to the number of the term from the list. Write in the table under each letter the corresponding number.
“The famous teacher V.A. Sukhomlinsky, speaking about the true beauty of a person, uses (A) __________ (spirituality, illumination, apotheosis, etc.), which gives the text an exalted sound and expresses his own position vividly and figuratively, using such expressive means as (B) _______ (glow of the soul , moral origins, the living blood of beauty). Reception (B) _________ (sentences 10, 11 and 20-22) helps the author to structure the text. Of the syntactic means of expression, it is worth noting (D) _____ (sentences 5, 21).
List of terms:
2) question-answer unity
4) metaphor
5) colloquial vocabulary
6) book vocabulary
7) antithesis
8) gradation
9) rhetorical question
Part 2
25. Write an essay on the text you read. Formulate one of the problems posed by the author of the text. Comment on the formulated problem. Include in the comment two examples-illustrations from the read text that, in your opinion, are important for understanding the problem of the source text (avoid excessive quoting). Formulate the position of the author (narrator). Write whether you agree or disagree with the point of view of the author of the read text. Explain why. Argue your opinion, relying primarily on the reader's experience, as well as on knowledge and life observations (the first two arguments are taken into account).
The volume of the essay is at least 150 words.
A work written without relying on the text read (not on this text) is not evaluated. If the essay is a paraphrase or a complete rewrite source text without any comments, then such work is rated 0 points.
Write an essay carefully, legible handwriting.
TRIAL USE 2017 Option 1
| job number | job number | ||
| to and moreover, to |
|||
| folded | 1347 any other sequence of these digits |
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| kindle | |||
| 12347 any other sequence of these digits |
|||
| haughty | 345 any other sequence of these digits |
||
| artlesshave have an artless | 125 any other sequence of these digits |
||
| command | internalexternalexternalinternal |
||
| spreads | |||
| malnourished | |||
| Part 2 |
|
| Text Information |
|
| Approximate range of problems | |
| 1. The problem of the true beauty of a person. | 1. The true beauty of a person is determined by the harmony of the physical, moral, aesthetic. |
| 2. The problem of the connection between the external beauty of a person and his inner world. | 2. External beauty is a manifestation of a person's inner spiritual strength. |
The average score of participants increased by almost 1 point compared to last year and amounted to 47.1 points. Number of participants who failed to overcome minimum threshold at 27 points, decreased by 1%. Total in the exam for specialized mathematics about 391 thousand participants took part.
“The level of complexity of the Unified State Examination in mathematics at the profile level in 2017 did not change. Preliminary results of the exam show that the participants did better this year. We can also state a more conscious choice of the USE level in mathematics by graduates: fewer participants signed up for both exams at once, the profile USE was chosen mainly by graduates who need mathematics to enter a university,” said Sergey Kravtsov, head of Rosobrnadzor.
Thanks to the introduction of scanning technology for the answer forms of USE participants at the examination points, the processing of the results was promptly completed. USE participants in mathematics at the profile level will be able to find out their result two days earlier due date. This can be done via Personal Area on the USE portal - http://check.site/.
June 28 in the main USE period 2017, there is a reserve period for passing the exam mathematics. The graduates of previous years who want to improve their result will be able to take the exam on this day. Also, the USE in mathematics will be able to retake the graduates of the current year, who received a positive result of the USE in the Russian language, but do not have a satisfactory USE result in mathematics, neither the basic nor the profile level. For retake, such graduates can choose any level of the USE in mathematics - profile or basic.
Preparation for the OGE in mathematics and for the USE in other subjects:
Tell me, would you like to spend the next 5 years in such a way that you remember them forever, so that they are the happiest in your life?
Would you like to be proud of yourself for the rest of your life?
And the most, perhaps, indiscreet question. Would you like to earn a lot more than the rest and be happier?
Ru. I have two higher education, several years of work in top international companies (PwC and E&Y), own consulting company...
But I started with I couldn't get into college.
For various reasons, but the most main reason- I DID NOT BELIEVE THAT I NEED IT. And I didn't prepare.
And so, after I failed, the fun began.
It was embarrassing...
Because I had to answer the questions many, many times: “How?! You didn't get in?! Why?! You are smart!” You can’t argue ... You can’t say: “No, I’m a fool ...”
Then I had to go to GPTU. Now it is called the beautiful word "College". And then this abbreviation was deciphered in a different way: "Lord, Help the Dumb One Settle Down."
In general ... it became completely unbearable. Because some of my friends did and somehow immediately became inaccessible.
They went to college, hung out in hostels, had fun, and I went to the factory and nailed the slats to the wooden panels on the conveyor and it was called training.
I took a panel, put slats on it, 12 shots with an air pistol and ... the next panel. And so 8 hours ... And so the whole life ...
And then there was the army - not the most pleasant place on earth. To be honest, it was real hell and just thrown out 2 years of life, so heavy that I could not even imagine.
A year of “study” at the GPTU (and in fact stupid, mechanical work at the factory) and two years of even more stupid and senseless service in the army were very convincing.
The value of education was clearly explained to me in a simple, intelligible way. I realized one thing...
I don't want to live like this!
I don't want to go to the factory, do mechanical work earn little.
And after the army, I gathered my strength and with great difficulty entered ... but not at the institute, but at the preparatory department, where they trained me for another year to enter the university.
It is unrealistic to enter a university directly after a three-year break in studies.
And only after the preparatory department, I was able to somehow “creep” on the budget to the institute. Not the best, but still...
There were two institutes, 6 years of the most beautiful fun!
After the second institute, I found a job and started getting more than my parents. AND the work was very interesting(much more interesting than nailing slats).
I went on business trips all over the country: I visited Nakhodka, Sakhalin, Baikal, the Arctic Circle, passed professional exams in the USA, went to training courses in Germany, Hungary. I interacted with very different interesting people, on the different languages. I made friends all over the world.
But… do you want to be honest?
It was incredibly difficult to get out of the hole into which I drove myself. I had to simultaneously earn my living, study, sleep very little, catch up all the time ...
Few can stand it.
Why am I telling all this? Not to brag. There is nothing to brag about here.
I can not understand…
Why did I so mediocrely miss the four best years of my life?!
And I encourage you to ask yourself a couple of questions right now...
Perhaps… you should be smarter than me? Perhaps it’s worth a little strain and enter the university of your dreams this year? Perhaps it's easier to enroll right after high school? Think. If the answer is yes, then read on...
On urgent preparation for the exam in mathematics
But first, one thought, which, I know, gnaws at many, many schoolchildren like you. Here she is:
I have no aptitude for mathematics. I won't be able to pass the exam.
Here's what I'll tell you about it. This is complete nonsense!
There are no people incapable of mathematics. There are people who are not capable of teaching it.
It may sound harsh, but it's true. Too many "teachers" are not capable of teaching.
The task of the teacher is not to demonstrate his knowledge (he should have it by definition), but to descend to the level of the student and climb with him at his pace along the steps of knowledge, explaining complex concepts on the fingers.
Maybe you just no luck with the teacher...
Look at the reviews for our textbook “For Dummies” on the site site. Pay attention to how many schoolchildren figured out difficult sections of mathematics for the first time thanks to the textbook and wrote to us about it!
Why is that?
Because we have created a textbook that explains complex mathematical concepts in a simple, human language. Because with the help of it you can deal with any topic in mathematics on your own.
For these schoolchildren (and their parents and even grandparents!) our textbook has become an excellent electronic teacher!
Another question that also worries you very much:
How difficult is the exam in mathematics ?!
Take a look yourself. Before you is a schedule of those who took the exam in various subjects for 100 points for 2018.
It can be seen from the graph that there are only 0.03% of those who took the test and that mathematics as well as English are the most difficult exams.
So you need to seriously prepare for them. But do not worry, if you are reading these lines, you will know how to pass this ill-fated USE in mathematics!
Why can our USE preparation program in mathematics and our textbook “For Dummies” help you prepare in the remaining time?
It's all about the interaction of the five parts of the site 100gia.ru and the site
See what these parts are:
The school does not prepare for the exam for admission to the top university on the budget!
It is not clear what needs to be repeated, what tasks to pay attention to when preparing!
Where I live there are no good teachers and you can't find a tutor!
Which of these issues apply to you?
Mathematics preparation program for the Unified State Examination
Our program for preparing for the exam in mathematics is your electronic tutor. Its algorithms were developed by the best tutors in Moscow. You don't have to look for other materials, you don't have to think about anything - just go from module to module and solve problems. Like in a game. If you can't, analyze the answers and solutions.
At school I had a weak math teacher. I did not get anything.
I got sick and dropped out. Couldn't catch up.
Mathematics is a very difficult subject, accessible only to geeks!
I don't have math skills!
Have we already said that this is nonsense?
Textbook "For dummies" to prepare for the exam in mathematics
You are 100% good at math. Read the reviews for our textbook. A lot of people have figured out complex topics on their own. We have written this tutorial in a way that is understandable so that anyone can understand any topic. In simple human language about complex things.
I understood the course of the solution correctly, but did not notice the trap and solved the problem incorrectly!
The tasks were so unfamiliar! They didn't give us that at school!
The theory is clear, but the practice is not enough!
I solved difficult problems correctly. I know a lot and tried very hard, but I made a mistake on some nonsense!
Familiar, right? Be sure that all the tasks will seem unfamiliar to you on the exam.
Trainers by type and by topic
So there's no point in deciding all the time typical tasks. You need to look for and solve original problems in order to learn to think and not be afraid if the task seems at first incomprehensible.
Our problems (especially complex ones) were invented by our mathematicians Elena Evgenievna Bashtova and Aleksei Sergeevich Shevchuk. The tasks are original, that is, unfamiliar. Just what you need. By solving them, you will learn to think and prepare for the exam in mathematics in the best possible way!
Do you know how often we hear this phrase?! Why it happens?! Because you have not adapted to stress, solving tasks for a while, you are not used to controlling time.
Trial exam in mathematics
This part will allow you get used to stress, learn to control time and find out your true level.
You can take a trial exam in mathematics unlimited. The program each time selects a new version of tasks from the base of 6000 tasks.
The result of the trial exam, the answers to each problem and the solutions you you will receive immediately!
- I can't bring myself to study. I need someone to help and motivate me!
- I'm not sure I have enough time. There is nothing left before the exam ... nothing!
- I need help. I don't like to study alone.
Everything is simple!
Parent's office
In the parent's office there is an opportunity to see all the statistics of your progress. It is impossible to deceive him. Only correctly solved problems are displayed.
Together with your parents, you will be able to accurately estimate how much time you need to study per day in order to have time to complete the entire Program before the exam.
Our authors: who are they?
What exactly will you get by purchasing our USE preparation program in mathematics and access to the textbook “For Dummies”
Mathematics preparation program for the Unified State Examination
- 25 geometry modules;
- 25 algebra modules;
- An entrance test that determines the level of the student and a training program adapted to his level;
- Just go like in a game, from module to module;
- Parent's office (to help the student).
A great option for those who want to study on their own.
Why super? because the most budget (but very high quality!).
Because prepared by the best tutors in Moscow as an electronic replacement for a tutor.
If you complete the Program to the end, increase your result by an average of 40%(according to a survey of students).
Simulators for solving problems by topic and type:
- 6000 tasks in the database for each topic and each type;
- All tasks with solutions and answers.
A great option for those who do not need a program, but need to get their hands on tasks on a specific topic or type.
to don't make stupid mistakes in simple tasks
to learn how to write the answer correctly
to achieve stability results
to step on all the rakes and learn solve problems with traps(of which there will be many on the exam)
not to be afraid to solve unknown problems (our problems are unique, you can’t download them on the Internet)
The best way to prepare with a simulator?
You read the topic in our textbook “For Dummies”, solve all the problems on the topic, and then solve all the problems on the same topic in the simulator.
Trial exam - unlimited.
- At any time, you can sit down and write a trial exam, for a while. And immediately get the result and analysis of tasks.
- Our trial exam is as close to the real one as possible.
You will know exactly what you are capable of.
And most importantly, you can feel exam stress(the test is for a while) and get used to it.
Parent's office.
You can help the student by complicating or vice versa simplifying his program.
can be assessed whether you have time to prepare for the exam or not, because you can see all the statistics of the student.
Textbook (written in human language)
You can understand any complex topic in mathematics just by reading a chapter from a textbook.
Don't believe?
Look at student reviews on any page of the textbook.
Where I live, no good teacher mathematics. I found your training course and practiced on my own for about 5 months. Plus I read your textbook and solved problems from it. Passed 78 points. For me, this is a lot! This is just a miracle! I recommend you to everyone!
Galya Ferzhikova
Was looking for inexpensive math courses for my son so I could figure it out and help him. I'm glad I stumbled across your course. Sometimes we studied together, sometimes separately, and now he is in his first year! I wish you and your project good luck!
Alexander Viktorovich Lovtsov
I took the exam 2 years ago when your course was free (thanks for that!). I have never been friends with mathematics, but your textbook helped a lot! I realized that I could master any topic. The preparation program was difficult at first, because I lied on your entrance test and got an advanced program. She's really complex. Then I passed the entrance test again and everything went fine. The ability to understand the material itself was very useful at the institute. I'm still reading the textbook :)
Galina K.- Student
Who is our textbook and training program for?
It is for the very smart, for the independent.
For those who do not have much money to hire tutors.
For those who are important to achieve everything on their own and then, at the institute, when neither dad, nor mother, nor tutors are around, not to get confused and get out of any situation.
Of course, we like the idea of studying with a tutor. But what about those who do not have much money to hire?
What to do with those who lives in a small village where there are no good tutors?
We think everyone should have a chance!
What do we not like about other USE preparation programs in mathematics and textbooks?
We don't like HOW most math textbooks are written.
It seems that they were written by people who knew and knew everything right from birth, and no one taught them addition, subtraction, multiplication, division, did not patiently explain tricky tasks step by step. On fingers. Understandable language.
No. They immediately knew how to “differentiate and integrate”, immediately understood the mathematical language as their native language.
Of course it wasn't. If they know math well, then someone messed with them, then they had a good teacher.
What is a good teacher?
This is not the one who knows everything and constantly demonstrates it, but the one who descends to the level of the student and climbs the steps of knowledge together with him, step by step, helping him so that he does not stumble.
In order for you to master something new, you first need to be explained to you on your fingers, then they will help you to consolidate it in practice, and only then you will be able to use this new skill very quickly.
It doesn't work otherwise.
That's what we tried to do in our tutorial.
What does our textbook and training program NOT do?
It's not just a theory. It's a focus on problem solving. Because at the exam in mathematics you will not be asked for theory, but for solving problems. If you need an ordinary textbook on theory - this is not for us.
They won't learn for you. If you're not in the mood to prepare, don't buy anything from us. We won't be able to help you.
For whom is our textbook and training program NOT suitable?
They won't work for you if you:
- unable to convince himself of the need to study;
- unable to regularly sit down, open the computer and study.
Or if you don't have someone to push and motivate you.
It can be your parents (In this case, open the parent's office for them so that they can see all your statistics and, if you are behind, help you)
It could be your friends. You can agree with a friend and open a parent's office for each other, compete with each other.
Thank you for the test exam!
I was very worried that my daughter would not cope with the excitement and she would not have enough time for a real exam. And here is your training program! We actually studied with a tutor, but on your site you only took a trial exam. Many many times.
The tasks are different all the time, but the daughter coped with them and this gave confidence. Passed the exam at 91!
Andrey Gusev
I have been using your sites since 8th grade. Mostly a textbook and training on topics. At school, they explain it incomprehensibly, your textbook is better!
If something is not clear, I first look at the tutorial and usually this is enough. But, if not, I solve problems in the simulator on the same topic until I feel that I understand everything.
OGE passed without problems. Now I'm preparing for the exam.
Irina Samoilova
Questions and answers:
What is on the site?e site?
The site contains our famous textbook “For Dummies”, written in human language, which allows you to understand the topic yourself. The explanation is “on the fingers”, very clear. If you look at the reviews under each topic, you can see how many students figured out difficult topics on their own.
What is on 100gia.ru website?
The site 100gia.ru contains:
- Preparation program for the Unified State Examination in mathematics and the OGE in mathematics, as well as preparation programs for grades 8 and 10 (for those who would like to prepare for exams in advance);
- Simulators for solving problems by topic and type. For those who do not need a full-fledged training program, but who need to get their hands on solving problems of a specific type or on a specific topic. The database contains more than 6000 tasks with solutions and answers.
- Trial exam in mathematics and trial OGE in mathematics. For those who need to understand their real level, identify weaknesses, feel the stress associated with lack of time and get used to it.
For what period is access to the textbook (website) given?
We give lifetime access to the textbook located on the site site. It is limited only by the lifetime of the site.
For what period of time do you give access to the site 100gia.ru?
We give lifetime access to all services located on the site 100gia.ru. It is limited only by the lifetime of the site.
Do you only prepare for the exam in mathematics?
Yes, we prepare only for the Unified State Examination and the OGE in mathematics.
How many options are available for the Trial USE in Mathematics and Trial OGE in Mathematics?
You can take the Trial USE and Trial OGE an unlimited number of times. The program generates a new list of tasks each time.
When are the results of the Trial USE in Mathematics and Trial OGE in Mathematics available if I pass them on your website?
Results are available instantly. You can also look at the correct answers and solutions to problems and understand where you made a mistake and what topics you need to tighten up. Further, these topics can be trained on simulators by topic or by type.
For what level of student preparation is your Training Program located on the 100gia.ru website suitable?
Our training program is suitable for any level of student preparation. Before the start of training, the student takes an entrance test and the system determines his level. Based on this level, the system develops a training program suitable for a particular student. Then the student learns according to his program, according to the principle “from simple to complex”, step by step, module by module, going through the entire program.
Where did you get the tasks from?
We wrote all 6000 tasks in the database ourselves. Simple tasks are like simple tasks from other sources because it's hard to come up with something original. But complex tasks are unique. Our mathematicians worked on them. They cannot be googled on the internet. Therefore, solving these problems will teach you to think and prepare you for the stress of the exam. It's no secret that on the exam, all tasks seem unfamiliar. So, this won't be a problem for you.
My child is writing. How can you help with this?
To be honest, it's hard to help in this situation. To get a high score on the exam, you need to learn to think, not write off. It takes time and work on your child's part. All that can be advised is to try to explain to the child the importance of the exam. It is most important. If you succeed, you can try to get as far as possible through the training program in the remaining time. You can open a parent's account, see all his successes and help him, praise, cheer...
What is the best way to study with our websites?
Option 1. You read the topic in our textbook “For Dummies”, solve all the problems on the topic, and then solve all the problems on the same topic in the simulator of the Preparatory Program for the Unified State Examination in Mathematics.
Option 2. Go through the Mathematics Preparation Program for the Unified State Examination and, if the topic is not clear, read the materials of the textbook “For Dummies” on this topic.
And now the story that I promised, that you should not give up under any circumstances.
1991 My friend is 24 years old. He is a 3rd year student. He has just had a baby, prices have been released in the country, and if he starts working in his profession after graduation, the money he will earn will not be enough for food... My wife and child live in a hostel in another city. That is, he and his family also have nowhere to live.
I don't know who told him, but he's in this situation For some reason I started learning English. In those days, it was not as easy as it is now, there were no good textbooks, courses, teachers themselves could not always speak English well. But he took the textbooks that fell into his hands and studied them from cover to cover.
When he announced to everyone that he would enter International University they laughed at him openly. The university was supervised by Russian President Yeltsin and Moscow Mayor Popov. The university gave out-of-towners a hotel room for two. No one believed that it was possible to enter there “from the street”.
Further, what my friend did ... He understood that he has absolutely no chance of getting in. because of English. He also knew that the exam would include an essay in English on a free topic. And he thought that the topic might be: “Why do you want to study at the International University?”.
Again, what were the chances that he would guess right? Very small...
My friend hired a tutor, wrote an essay with him on this topic and memorized it to the comma. He wanted to write a few more essays on other topics, but he had no more money for a tutor.
And then he took and for some reason corrected one sentence in this essay - made it more grammatically complex, the same as in one grammar textbook ...
Exam
English was the last exam. And - a miracle! Indeed, there was such a topic in the essay and my friend diligently rewrote everything to the comma got 23 points out of 25 possible!
Did it help him?
Despite all efforts, he was 12th in the list of 10 budget places. It looks like you could give up. He did everything he could. But this guy wasn't like that.
He went to challenge the work on English language, because this is the only thing that could be challenged (mathematics and Russian could not be challenged). Although even if he was given 25 points out of 25, he still would not be enough to get into the top ten lucky ones. But he went...
He asked why he was given 23 points and not 25? The teacher replied that the essay was great, but he had one stylistic mistake and pointed to the SAME sentence that my friend corrected!
Imagine what a shame! He ruined everything with his own hands! End?
Yeah .. right now!
A friend finds the same grammar textbook right there in the department, opens it on a page with an example of that very complex grammatical construction and shows the teacher: “This is not a mistake, but a stylistic device.”
The teacher looks and gets inspired: “Ah, so that's what you meant! That's interesting... Okay. I’ll give you 25 points… and I’ll add another 2 points for my deep knowledge of the English language!”
Bingo! 27 points out of 25 possible! Just unbelieveble!
Did the guy get in?
It wasn't there. He became 11th in the list of 10 budget places ...
And then he had a dilemma. It was possible to transfer to another faculty, where he would have had enough points, but this faculty, as he thought then, was not so interesting and he decided not to twitch, hoping that someone in front of him would leave the race ...
If you do not give up and do everything to be lucky, you will be lucky to the end!
And so it happened. Two girlfriends in front of him were transferred to the same easier faculty. They wanted to study together, but one of them didn't pass...
And he finished 10th...
International University changed everything in his life. He built an excellent career and everything is fine with him now.
Conclusion?
NEVER GIVE UP, MY FRIEND!
NEVER GIVE UP MY FRIEND!
You have… 3 months left.
Or already 2 or even 1 ... day! - never mind!
Do not give up!
Take our textbook and learn as much as you can before the exam. Learn to solve problems in our simulator. Or take the Training Program and go through it as much as you can.
Try your best. Do not give up!
One day left?
Learn ONE topic and learn how to solve problems on it.
Perhaps this topic will give you those same 27 points out of 25 that EVERYONE will decide.
The video course "Get an A" includes all the topics you need to successful delivery USE in mathematics for 60-65 points. Completely all tasks 1-13 profile exam mathematics. Also suitable for passing the Basic USE in mathematics. If you want to pass the exam with 90-100 points, you need to solve part 1 in 30 minutes and without mistakes!
Preparation course for the exam for grades 10-11, as well as for teachers. Everything you need to solve part 1 of the exam in mathematics (the first 12 problems) and problem 13 (trigonometry). And this is more than 70 points on the Unified State Examination, and neither a hundred-point student nor a humanist can do without them.
All the necessary theory. Quick solutions, traps and secrets of the exam. All relevant tasks of part 1 from the Bank of FIPI tasks have been analyzed. The course fully complies with the requirements of the USE-2018.
The course contains 5 large topics, 2.5 hours each. Each topic is given from scratch, simply and clearly.
Hundreds of exam tasks. Text problems and probability theory. Simple and easy to remember problem solving algorithms. Geometry. Theory, reference material, analysis of all types of USE tasks. Stereometry. Cunning tricks for solving, useful cheat sheets, development of spatial imagination. Trigonometry from scratch - to task 13. Understanding instead of cramming. Visual explanation of complex concepts. Algebra. Roots, powers and logarithms, function and derivative. Base for solving complex problems of the 2nd part of the exam.
